Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 470: 87

Answer

$x=e^{\frac{k}{p-a}}$

Work Step by Step

The given expression can be written as: $p-a =\dfrac{k}{\ln x}$ or, $p-a \ln x= k$ or, $\ln x= \dfrac{k}{p-a}$ Therefore, our answer is: $x=e^{\frac{k}{p-a}}$
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