Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 470: 95

$A= \dfrac{B}{x^C}$

The given expression can be written as: $\log A=\log B- C \log x$ Apply logarithmic property : $\log \dfrac{a}{b}=\log a - \log b$ and $\log a^ b=b \log a$ . $\implies \log A=\log \dfrac{B}{x^C}$ Therefore, our answer is: $A= \dfrac{B}{x^C}$