Answer
$ M=M_0\cdot 10^{\frac{6-m}{2.5}} $
Work Step by Step
$m=6-2.5\ log(\frac{M}{M_0})\longrightarrow log(\frac{M}{M_0})=\frac{6-m}{2.5} \longrightarrow \frac{M}{M_0}=10^{\frac{6-m}{2.5}} \longrightarrow M=M_0\cdot 10^{\frac{6-m}{2.5}} $
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.5 Exponential and Logarithmic Equations - 4.5 Exercises - Page 470: 94
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