Answer
(a) domain $(-\infty,\infty)$, range $(-\infty,\infty)$.
(b) $f(x)=\frac{1}{4}x+\frac{3}{2}$. $f(-2)=1$
Work Step by Step
(a) Given $x-4y=-6$, we can find the domain as $(-\infty,\infty)$ and range as $(-\infty,\infty)$.
(b) Rewrite the equation as $y=\frac{1}{4}x+\frac{3}{2}$, we have $f(x)=\frac{1}{4}x+\frac{3}{2}$. For $x=-2$, we have $f(-2)=\frac{1}{4}(-2)+\frac{3}{2}=1$
