Answer
(a) domain $[-5,\infty)$ and range $(-\infty,\infty)$.
(b) not a function.
Work Step by Step
(a) Given $y^2-x=5$, we have $x=y^2-5$, we can find the domain as $[-5,\infty)$ and range as $(-\infty,\infty)$.
(b) Rewrite the equation as $y=\pm(x+5)$, and this does not form a function.
