## Precalculus (6th Edition)

(a) $f(-5)=-7$ (b) $f(-1)=-3$ (c) $f(0)=-2$ (d) $f(3)=2$
To evaluate the piecewise-defined function, identify the 'piece' of the function that covers the given value of $x$. Then substitute, the given value of $x$. (a) $f(-5)$ For $x=-5$ the function is defined by $x-2$. Thus, $f(-5) = -5-2=-7$ (b) $f(-1)$ For $x=-1$ the function is defined by $x-2$. Thus, $f(-1) = -1-2=-3$ (c) $f(0)$ For $x=0$ the function is defined by $x-2$. Thus, $f(0) = 0-2=-2$ (d) $f(3)$ For $x=3$ the function is defined by $5-x$. Thus, $f(3) = 5-3=2$