Answer
Yes, center $(0,4)$, radius $5$.
Work Step by Step
Step 1. Given $x^2+y^2-8y-9=0$, we have $x^2+y^2-8y=9$
Step 2. Form perfect squares: $x^2+y^2-8y+16=9+16$, we have $x^2+(y-4)^2=5^2$
Step 3. The above equation forms a circle with center at $(0,4)$ and radius $r=5$.
