## Precalculus (6th Edition)

(a) $f(2)=15$ (b) $f(-1)=10$
(a) The value of $f(2)$ is the range element paired with the domain element $2$. The domain element $2$ is paired with the range element $15$. Thus, $f(2) = 15$. (b) The value of $f(-1)$ is the range element paired with the domain element $-1$. The domain element $-1$ is paired with the range element $10$. Thus, $f(-1) = 10$.