Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.3 Functions - 2.3 Exercises - Page 216: 57



Work Step by Step

To find the value of $g(\frac{1}{2})$, substitute $\frac{1}{2}$ to $x$ in $g(x)$ to obtain: $g(x)=-x^2+4x+1 \\g(\frac{1}{2})=-(\frac{1}{2})^2+4(\frac{1}{2})+1 \\g(\frac{1}{2})=-\frac{1}{4}+2+1 \\g(\frac{1}{2})=-\frac{1}{4}+3 \\g(\frac{1}{2})=-\frac{1}{4}+\frac{12}{4} \\g(\frac{1}{2})=\frac{11}{4}=2.75$
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