Answer
The given relation defines $y$ as a function of $x$.
domain: $(-\infty, 5) \cup (5, +\infty)$
range: $(-\infty, 0) \cup (0, +\infty)$
Work Step by Step
The given equation will give only one value of $y$ for every value of $x$ within its domain. This means that each $x$ is paired with only one value of $y$.
Thus, the given relation defines $y$ as a function of $x$.
The denominator is not allowed to be zero.
Since $5$ will make the given expression's denominator equal to zero, then $x$ cannot be $5$. Thus, the domain is $(-\infty, 5) \cup (5, +\infty)$.
Note that when $-7$ is divided by any non-zero number, the quotient will never be equal to zero. Thus, the value of $y$ can be any real number except zero. In interval notation, the range is $(-\infty, 0) \cup (0, +\infty)$.
