Work Step by Step
To find the value of $f(3t-2)$, substitute $3t-2$ to $x$ in $f(x)$ to obtain: $f(x)=-3x+4 \\f(3t-2)=-3(3t-2)+4 \\f(3t-2) = -3(3t) +(-3)(-2)+4 \\f(3t-2)=-9t+6+4 \\f(3t-2)=-9t+10$
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