Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.3 Functions - 2.3 Exercises - Page 216: 66



Work Step by Step

To find the value of $f(3t-2)$, substitute $3t-2$ to $x$ in $f(x)$ to obtain: $f(x)=-3x+4 \\f(3t-2)=-3(3t-2)+4 \\f(3t-2) = -3(3t) +(-3)(-2)+4 \\f(3t-2)=-9t+6+4 \\f(3t-2)=-9t+10$
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