Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises - Page 194: 61

Answer

$\color{blue}{\bf{\text{Quadrants 3, 1, 4, & 4 respectively}}}$

Work Step by Step

Remember that quadrants start at positive $x$ and $y$ values and run counter-clockwise: $\bf{\text{Quadrant 1} = (+x, +y)}$ $\bf{\text{Quadrant 2} = (-x, +y)}$ $\bf{\text{Quadrant 3} = (-x, -y)}$ $\bf{\text{Quadrant 4} = (+x, -y)}$ If $\bf{(a,b)}$ is in $\bf\text{Quadrant 2}$, than it must be in the form: $\bf{(−x,+y)}$ Therefore, $\bf{a}$ must be a$\bf{ \text{ negative }}$value, and $\bf{b}$ must be a $\bf{ \text{positive }}$value $\bf{(a,-b)}$ = $\bf{(-x,-y)}$ which is in $\color{blue}{\bf{\text{Quadrant 3}}}$ $\bf{(-a,b)}$ = $\bf{(x, y)}$ which is in $\color{blue}{\bf{\text{Quadrant 1}}}$ $\bf{(-a,-b)}$ = $\bf{(x, -y)}$ which is in $\color{blue}{\bf{\text{Quadrant 4}}}$ $\bf{(b,a)}$ = $\bf{(x, -y)}$ which is in $\color{blue}{\bf{\text{Quadrant 4}}}$
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