Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises - Page 194: 51

Answer

$\bf \color {blue}{(0,0),(1,1),(-2,4)}$ $\bf \color {blue}{\text{or any other point on the parabola}}$

Work Step by Step

$$\bf{y=x^2}$$ $\bf \text{Lets plug in numbers to find three points}$ if $x=0$: $y=(0)^2$ $y=0$ $\bf \color {blue}{(0,0)}$ if $x=1$: $y=(1)^2$ $y=1$ $\bf \color {blue}{(1,1)}$ if $x=-2$: $y=(-2)^2$ $y=4$ $\bf \color {blue}{(-2,4)}$ So three of the points are: $\bf \color {blue}{(0,0),(1,1),(-2,4)}$ Which we can graph as a parabola:
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