Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises - Page 194: 54

Answer

$\bf \color {blue}{(0,-3),(9,0),(1,-2)}$

Work Step by Step

$$\bf{y=\sqrt{x}-3}$$ $\bf \text{Lets plug in numbers to find three points}$ if $x=0$: $y=\sqrt{0}-3$ $y=-3$ $\bf \color {blue}{(0,-3)}$ if $y=0$: $0=\sqrt{x}-3$ $3=\sqrt{x}$ $x=9$ $\bf \color {blue}{(9,0)}$ if $x=1$: $y=\sqrt{1}-3$ $y=1-3$ $y=-2$ $\bf \color {blue}{(1,-2)}$ So three of the points are: $\bf \color {blue}{(0,-3),(9,0),(1,-2)}$ Which we can graph as:
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