## Precalculus (6th Edition)

$120,\qquad 30,240$
Positions in basketball are often referred to as 1-5. Order is important $\rightarrow$ we count permutations $P(n,r)=\displaystyle \frac{n!}{(n-r)!}$. For r=5 players taken from n=5 players, $P(5,5)=5!=120$ For r=5 players taken from n=10 players, $P(10,5)=\displaystyle \frac{10!}{5!}=30,240$