Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.6 Basics of Counting Theory - 11.6 Exercises - Page 1062: 46

Answer

$604,800$

Work Step by Step

Arrangements $\rightarrow$ Permutations.$P(n,r)=\displaystyle \frac{n!}{(n-r)!}$. Arranging r=$7$ from n=$10$ rats, $ P(10,7)=\displaystyle \frac{10!}{(10-7)!}\qquad$ ... $=\displaystyle \frac{10\times 9\times 8\times 7\times 6\times 5\times 4\times(3!)}{(3!)}$ $=10\times 9\times 8\times 7\times 6\times 5\times 4$ = $604,800$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.