Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.6 Basics of Counting Theory - 11.6 Exercises - Page 1062: 51

Answer

$a.\quad 120$ $b.\quad 6$

Work Step by Step

Arrangements are permutatitons. $P(n,r)=\displaystyle \frac{n!}{(n-r)!}$ $a.$ $r=5,n=5$ $P(5,5)=5!=120$ $b.$ $r=3, n=3$ $P(3,3)=3!=6$
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