Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.6 Basics of Counting Theory - 11.6 Exercises - Page 1062: 47



Work Step by Step

Arrangements $\rightarrow$ Permutations.$P(n,r)=\displaystyle \frac{n!}{(n-r)!}$. Arranging r=$3$ from n=$6$ available courses, $ P(6,3)=\displaystyle \frac{6!}{(6-3)!}\qquad$ ... $=\displaystyle \frac{6\times 5\times 4\times(3!)}{(3!)}$ $=6\times 5\times 4$ = $120$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.