Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises: 7

Answer

$3$

Work Step by Step

From the graph we get $a_{1}=-4;a_{2}=-1;a_{3}=2;a_{4}=5;a_{5}=8$ So the common difference is $d=a_{n+1}-a_{n}=a_{5}-a_{4}=a_{4}-a_{3}=a_{3}-a_{2}=a_{2}-a_{1}=8-5=5-2=2-\left( -1\right) =\left( -1\right) -\left( -4\right) =3$
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