Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1024: 30


$a_n=y-3n+7$ $a_8=y-17$

Work Step by Step

$a_2=y+1$ $d=-3$ Find $a_1$: $a_2=a_1+d$ $y+1=a_1+(-3)$ $a_1=y+4$ $a_n=a_1+(n-1)d$ $a_n=(y+4)+(n-1)*(-3)$ $a_n=y+4-3n+3$ $\boxed{a_n=y-3n+7}$ $a_8=y-3*8+7$ $a_8=y-24+7$ $\boxed{a_8=y-17}$
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