Answer
$a_n=3+2n$
$a_8=19$
Work Step by Step
$5, 7, 9, ...$
We have $a_1=5$ and $d=7-5=2$.
Using the formula $a_n=a_1+(n-1)d$, we get:
$a_n=5+(n-1)*2$
$a_n=5+(2n-2)$
$\boxed{a_n=3+2n}$
$a_8=3+2*8=3+16=\boxed{19}$.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1024: 23
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
