Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.1 Parabolas - 10.1 Exercises - Page 967: 41

Answer

$${y^2} = \frac{4}{3}x$$

Work Step by Step

$$\eqalign{ & {\text{The parabola is symmetric with respect to the }}x{\text{ - axis, then }} \cr & {\text{the equation is of the form }}{y^2} = 4px \cr & {\text{The point }}\left( {3,2} \right){\text{ is on the graph, it must satisfy the equation}}{\text{.}} \cr & {y^2} = 4px \cr & {\left( 2 \right)^2} = 4p\left( 3 \right) \cr & 4 = 4p\left( 3 \right) \cr & p = \frac{1}{3} \cr & {\text{Then, the equation is:}} \cr & {y^2} = 4\left( {\frac{1}{3}} \right)x \cr & {y^2} = \frac{4}{3}x \cr} $$
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