Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.1 Parabolas - 10.1 Exercises - Page 967: 24

Answer

$$\eqalign{ & {\text{focus: }}\left( {0,\frac{1}{{32}}} \right) \cr & {\text{directrix: }}y = - \frac{1}{{32}} \cr & {\text{axis of symmetry: }}x = 0 \cr} $$

Work Step by Step

$$\eqalign{ & {x^2} = \frac{1}{8}y \cr & {\text{This equation is written in the form }}{x^2} = 4py.{\text{ }} \cr & {\text{represents a parabola with Vertical Axis }} \cr & {\text{of Symmetry and Vertex }}\left( {0,0} \right). \cr & \underbrace {{x^2} = \frac{1}{8}y}_{{x^2} = 4py} \cr & \frac{1}{8}y = 4py \cr & p = \frac{1}{{32}} \cr & {\text{With focus}}\left( {0,p} \right){\text{ and directrix }}y = - p \cr & {\text{focus: }}\left( {0,\frac{1}{{32}}} \right) \cr & {\text{directrix: }}y = - \frac{1}{{32}} \cr & {\text{axis of symmetry: }}x = 0 \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.