Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.2 Applications and Modeling with Linear Equations - 1.2 Exercises - Page 102: 30


$120$ mL

Work Step by Step

The given table has the last column with values $\left[\begin{array}{l} 0.05x\\ 0.20(60)=12\\ 0.10(x+60) \end{array}\right]$ The equation to solve is $ 0.05x+12=0.10(x+60)\qquad$ ... multiply with 100 $5x+1200=10(x+60)$ $ 5x+1200=10x+600\qquad$ ... add $(-5x-600)$ $600=5x$ $x=\displaystyle \frac{600}{5}=120$ mL
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