Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.2 Applications and Modeling with Linear Equations - 1.2 Exercises - Page 102: 27

Answer

$35$ km

Work Step by Step

Distance traveled = (average speed)(time of travel). Let $s$ be the boat speed on placid water (with no currents). Sailing against the current, her average speed was $(s-5)$ km/h, and with the time it took (20 min$=\displaystyle \frac{20}{60}=\frac{1}{3}$hr), she covered $(s-5)\displaystyle \cdot\frac{1}{3}$ km. Downstream, her speed was $(s+5)$ km/h, and the time was $15$min$=\displaystyle \frac{1}{4}$h. The distance she covered was $(s+5)\displaystyle \cdot\frac{1}{4}$ km. The distances discussed are equal. $(s-5)\displaystyle \cdot\frac{1}{3}=(s+5)\cdot\frac{1}{4}\qquad$ ... multiply both sides by 12 (LCM of 3 and 4) $4(s-5)=3(s+5)$ $ 4s-20=3s+15\qquad$ ... add $20-3s$ $s=35$ km
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