Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.2 Applications and Modeling with Linear Equations - 1.2 Exercises - Page 102: 23


$45$ minutes ( or 0.75 hours)

Work Step by Step

Distance traveled by either runner = (average speed)(time of travel). If the speed is given in mph, the time is expressed in hours. After t hours, Mary covers $7t$ miles. Janet covers $5t$ miles. We want the time t at which Mary has covered 1.5 mi more than Janet (Mary's distance) = (Janet's distance) +1.5 $7t=5t+1.5$ $2t=1.5$ $t=0.75$ hours In minutes, $0.75(60)=45$ minutes
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.