Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 109: 169

Answer

The solution of the equation $V=C-\frac{C-S}{L}N$ for $C$ is $\frac{LV-NS}{L-N}$.

Work Step by Step

Consider the equation $V=C-\frac{C-S}{L}N$. Multiply $L$ on both sides of the equation. $VL=\left( C-\frac{C-S}{L}N \right)L$ Use the distributive property to solve the above equation. $\begin{align} & VL=\left( C-\frac{C-S}{L}N \right)L \\ & VL=CL-CN+SN \\ & VL=C\left( L-N \right)+SN \end{align}$ Subtract $SN$ from both sides. $\begin{align} & VL-SN=C\left( L-N \right)+SN-SN \\ & VL-SN=C\left( L-N \right) \end{align}$ Divide $\left( L-N \right)$ on both sides. $\begin{align} & \frac{VL-SN}{\left( L-N \right)}=\frac{C\left( L-N \right)}{\left( L-N \right)} \\ & C=\frac{VL-SN}{\left( L-N \right)} \\ & =\frac{LV-NS}{L-N} \end{align}$ The value of $C$ is $\frac{LV-NS}{L-N}$.
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