Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 109: 167


$ b=2$

Work Step by Step

If the solution set is $\{-6\}$, by substituting $ x=-6$ into the equation, it should be true. $\displaystyle \frac{7(-6)+4}{b}+13=-6\qquad $ ... we now solve this for b ... subtract 13 $\displaystyle \frac{-38}{b}=-19\qquad $ ... multiply with b $-38=-19b\qquad $ ... divide with $-19$ $ b=2$
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