Answer
The statement is false.
To make it true, replace "cannot" with "can".
Work Step by Step
EVERY quadratic equation can be solved by the quadratic formula
Here,$ b=0$ and
$ x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}=\frac{0\pm\sqrt{0-4ac}}{2a}$
$=\displaystyle \frac{\pm 2\sqrt{-ac}}{2a}=\frac{\pm\sqrt{-ac}}{a}$
Solving by the square-root-property method, $ ax^{2}=-c $
$ x^{2}=-\displaystyle \frac{c}{a}$
$ x= \displaystyle \pm\sqrt{\frac{-c}{a}} =\pm\frac{\sqrt{-c}}{\sqrt{a}}\cdot\frac{\sqrt{a}}{\sqrt{a}}$
$=\displaystyle \frac{\pm\sqrt{-ac}}{a}$
(the same solution)
The statement is false.
To make it true, replace "cannot" with "can".
