Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 84: 7


$\displaystyle \frac{3}{x-3}, \qquad x\neq 3$

Work Step by Step

Numerator, factored:$\qquad$ $3x-9=3(x-3)$ Denominator, factored: $x^{2}-6x+9=x^{2}-2\cdot x\cdot 3+3^{2}$=$\qquad$ ...recognize a square of a sum $=(x-3)^{2}=(x-3)(x-3)$ Numbers to be excluded from the domain are numbers that yield 0 in the denominator: $x\neq 3$ Expression = $\displaystyle \frac{3(x-3)}{(x-3)(x-3)}$=$\qquad$... cancel $(x-3)$ = $\displaystyle \frac{3}{x-3}, \qquad x\neq 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.