#### Answer

$x=\pm7$ must be excluded from the domain

#### Work Step by Step

The denominator can't equal zero.
$x^2 - 49=0$
$x^2=49$
$x=\pm\sqrt {49}=\pm7$

Published by
Pearson

ISBN 10:
0-13446-914-3

ISBN 13:
978-0-13446-914-0

$x=\pm7$ must be excluded from the domain

The denominator can't equal zero.
$x^2 - 49=0$
$x^2=49$
$x=\pm\sqrt {49}=\pm7$

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