Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 84: 15


$=\displaystyle \frac{1}{3},\qquad x\neq 2,-3$

Work Step by Step

Factor what you can: $x-2$ is factored $3x+9=3(x+3)$ $2x+6=2(x+3)$ $2x-4=2(x-2)$ expression $=\displaystyle \frac{x-2}{3(x+3)}\cdot\frac{2(x+3)}{2(x-2)}\qquad$ ...exclude the values that yield 0 in the denominator: $x\neq 2,-3$ ... cancel common factors: $2,\ (x-2)$, and $(x+3)$ $=\displaystyle \frac{1}{3},\qquad x\neq 2,-3$
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