Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Concept and Vocabulary Check: 9

Answer

$\sqrt{10}+\sqrt{2}$

Work Step by Step

The given expression's denominator can be rationalized by multiplying the conjugate denominator's conjugate to both the numerator and the denominator. RECALL: The conjugate of $\sqrt{a} - \sqrt{b}$ is $\sqrt{a}+\sqrt{b}$. Thus, the conjugate of the denominator is $\sqrt{10}+\sqrt{2}$. Thus, to rationalize the denominator of the given expression, multiply the numerator and the denominator by $\sqrt{10}+\sqrt{2}$.
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