Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Concept and Vocabulary Check: 3

Answer

$|a|$

Work Step by Step

RECALL: For any real number $a$, $\sqrt{a^2} = |a|$. Thus, $\sqrt{a^2} = |a|.$
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