## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Section P.3 - Radicals and Rational Exponents - Concept and Vocabulary Check - Page 45: 3

#### Answer

$|a|$

#### Work Step by Step

RECALL: For any real number $a$, $\sqrt{a^2} = |a|$. Thus, $\sqrt{a^2} = |a|.$

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