Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.3 - Radicals and Rational Exponents - Concept and Vocabulary Check - Page 45: 14


$2$; $8$

Work Step by Step

Note that $16=2^4$. RECALL: $a^{\frac{m}{n}}=(\sqrt[n]{a})^m$. Use the rule above: $16^{\frac{3}{4}} \\=(\sqrt[4]{16})^3 \\=(\sqrt[4]{2^4})^3 \\=(2)^3 \\=8.$ Thus, the missing expressions are $2$ and $8$.
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