Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.1 - Algebraic Expressions, Mathematical Models, and Real Numbers - Exercise Set: 56


$13-\sqrt 5$

Work Step by Step

Since $\sqrt 5 - 13$ is negative, we must negate it to find the distance from 0 and, therefore, the absolute value: $-(\sqrt 5 - 13) = 13-\sqrt 5$. Therefore, $|\sqrt 5 - 13| = 13-\sqrt 5$.
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