Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.1 - Algebraic Expressions, Mathematical Models, and Real Numbers - Exercise Set: 11

Answer

$46$

Work Step by Step

Start with expression: $x^{2}-3(x-y),x=8,y=2$. Substitute $8$ in for $x$ and $2$ in for $y$: $8^{2}-3(8-2)$. Simplify for answer: $64-3(6)=64-18=46$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.