## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter P - Section P.1 - Algebraic Expressions, Mathematical Models, and Real Numbers - Exercise Set - Page 17: 11

#### Answer

$46$

#### Work Step by Step

Start with expression: $x^{2}-3(x-y),x=8,y=2$. Substitute $8$ in for $x$ and $2$ in for $y$: $8^{2}-3(8-2)$. Simplify for answer: $64-3(6)=64-18=46$.

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