Precalculus (6th Edition) Blitzer

Published by Pearson

Chapter P - Section P.1 - Algebraic Expressions, Mathematical Models, and Real Numbers - Exercise Set - Page 17: 53

Answer

$12-\pi$

Work Step by Step

Since $12-\pi$ is positive, taking the absolute value of it does not change the sign. $|12-\pi| = 12-\pi$.

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