## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 9 - Section 9.5 - Parametric Equations - Exercise Set - Page 1019: 6

#### Answer

$(-1,4)$

#### Work Step by Step

The line passing through the point $P(a,b,c)$ and parallel to the normal vector $n=\lt p,q,r\gt$ can be represented by the parametric equations as shown below: $x=a+pt; y=b+qt; z=c+qt$ Here, $t \to$ Real number. Now, plug in the data. Therefore, $x=2+3 \cos 180^{\circ}=-1; y=4+2 \sin 180^{\circ}=4$ So, point is: $(-1,4)$

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