Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.5 - Parametric Equations - Exercise Set - Page 1019: 7


$(60 \sqrt 3,1)$

Work Step by Step

The line passing through the point $ P(a,b,c)$ and parallel to the normal vector $ n=\lt p,q,r\gt $ can be represented by the parametric equations as shown below: $ x=a+pt; y=b+qt; z=c+qt $ Here, $ t \to $ Real number. Now, plug in the data. Therefore, $ x=120 \cos 30^{\circ}=120 \times \dfrac{\sqrt 3}{2} =60 \sqrt 3 \\ y=120 \sin 30^{\circ}-59=1$ So, the point is: $(60 \sqrt 3,1)$
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