Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.5 - Parametric Equations - Exercise Set - Page 1019: 41

Answer

$(x-h)^2+(y-k)^2=r^2$

Work Step by Step

Re-arrange the parametric equations as shown below: $\cos t=\dfrac{x-h}{r}$ and $\sin t=\dfrac{y-k}{r}$ Since, $\sin^2 t+\cos^2 t=1$ $\implies (\dfrac{y-k}{r})^2 + (\dfrac{x-h}{r})^2=1$. or, $(y-k)^2+(x-h)^2=r^2$ Therefore, $(x-h)^2+(y-k)^2=r^2$
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