## Precalculus (6th Edition) Blitzer

$(2,4,-3)$
Step 1. Multiply $-2$ to the first equation and add to the second: $16y-3z=73$ Step 2. Multiply $-3$ to the first equation and add to the third: $16y+5z=49$ Step 3. Take the difference between the above two equations: $8z=-24$, thus $z=-3$ Step 4. Solve by back-substitution: $y=4, x=2$ Step 5. Thus, the solution to the system is $(2,4,-3)$