Answer
a. $x=\pm4$
b. See explanations
Work Step by Step
a. The x-intercepts can be found by letting $y=0$. We have $x^2=16$ and $x=\pm4$
b. If we try to find the y-intercept by letting $x=0$, we get $y^2=-9$ which has no real solution. Thus there is no y-intercept.
