Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.1 - The Ellipse - Exercise Set - Page 968: 95

Answer

$\frac{x^2}{9}-\frac{y^2}{4}=1$

Work Step by Step

By dividing $36$ on both sides, we get $\frac{x^2}{9}-\frac{y^2}{4}=1$ and this equation differs from that of an ellipse in that the sign in the middle is negative.
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