Answer
See graph and explanations.
Work Step by Step
Step 1. Graph the equation as shown in the figure.
Step 2. Rewrite the equation as $\frac{x^2}{49}-\frac{y^2}{4}=1$; we have $a=7, b=2$ and thus $c=\sqrt {7^2+2^2}=\sqrt {53}$
Step 3. As the center of the ellipse is at $(0,0)$ and the major axis is horizontal, the foci are $(\pm\sqrt {53},0)$ and the asymptotes are $y=\pm \frac{2}{7}x$ as shown in the figure.
