Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Mid-Chapter Check Point - Page 1000: 29



Work Step by Step

Step 1. From the given conditions, we have $2p=5+1=6$ or $p=3$ Step 2. The center is at $(4,\frac{5-1}{2})$ or $(4,2)$; thus we can write the equation as $(x-4)^2=4(3)(y-2)$ or $(x-4)^2=12(y-2)$
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