## Precalculus (6th Edition) Blitzer

$(y-6)^2=-20(x-3)$
Step 1. From the given conditions, we have $2p=8+2=10$ or $p=5$. As the directrix is above the focus, the parabola opens downwards. Step 2. The center is at $(\frac{8-2}{2},6)$ or $(3,6)$; thus we can write the equation as $(y-6)^2=-4(5)(x-3)$ or $(y-6)^2=-20(x-3)$