Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Mid-Chapter Check Point - Page 1000: 30



Work Step by Step

Step 1. From the given conditions, we have $2p=8+2=10$ or $p=5$. As the directrix is above the focus, the parabola opens downwards. Step 2. The center is at $(\frac{8-2}{2},6)$ or $(3,6)$; thus we can write the equation as $(y-6)^2=-4(5)(x-3)$ or $(y-6)^2=-20(x-3)$
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