Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.3 - Matrix Operations and Their Applications - Exercise Set - Page 918: 50

Answer

$CZ=\left[ \begin{matrix} -x \\ y \\ \end{matrix} \right]$ and it is a reflection about the $y\text{-axis}$ because the multiplication changes the sign of the $x\text{-coordinate}$.

Work Step by Step

To find CZ, multiply both matrices. That is, $$ $\begin{align} & CZ=\left[ \begin{matrix} -1 & 0 \\ 0 & 1 \\ \end{matrix} \right]\left[ \begin{matrix} x \\ y \\ \end{matrix} \right] \\ & =\left[ \begin{matrix} -1\times x+0\times y \\ 0\times x+1\times y \\ \end{matrix} \right] \\ & =\left[ \begin{matrix} -x \\ y \\ \end{matrix} \right] \end{align}$ $$ The multiplication changes the sign of the $x\text{-coordinate}$. Therefore, it is a reflection about the $y\text{-axis}$.
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