Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Cumulative Review Exercises - Page 952: 9


The inverse function is, ${{f}^{-1}}\left( x \right)=\frac{1}{4}\left( {{x}^{2}}+7 \right)$

Work Step by Step

Consider the given function, $y=\sqrt{4x-7}$ Square both sides to get, $\begin{align} & {{y}^{2}}=4x-7 \\ & x=\frac{1}{4}\left( {{y}^{2}}+7 \right) \end{align}$ Therefore, ${{f}^{-1}}\left( x \right)=\frac{1}{4}\left( {{x}^{2}}+7 \right)$
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