Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Cumulative Review Exercises - Page 952: 2


The solution is, $x\ge \frac{1}{2}$.

Work Step by Step

Consider the given inequality; $\begin{align} & 5x+8\le 7\left( 1+x \right) \\ & 5x-7x\le 7-8 \\ & -2x\le -1 \\ & x\ge \frac{1}{2} \end{align}$ The solutions of the inequalities are $x\ge \frac{1}{2}$.
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