Answer
The solution is, $x\ge \frac{1}{2}$.
Work Step by Step
Consider the given inequality;
$\begin{align}
& 5x+8\le 7\left( 1+x \right) \\
& 5x-7x\le 7-8 \\
& -2x\le -1 \\
& x\ge \frac{1}{2}
\end{align}$
The solutions of the inequalities are $x\ge \frac{1}{2}$.
