## Precalculus (6th Edition) Blitzer

The solution is, $x\ge \frac{1}{2}$.
Consider the given inequality; \begin{align} & 5x+8\le 7\left( 1+x \right) \\ & 5x-7x\le 7-8 \\ & -2x\le -1 \\ & x\ge \frac{1}{2} \end{align} The solutions of the inequalities are $x\ge \frac{1}{2}$.